The four quantum numbers of the outermost orb | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electronic configuration of $K$ $(Z = 19)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^1$. The outermost electron is in the $4s$ orbital. For the $4s

Vedclass · Accepted Answer

$n = 4, l = 0, m = 0, s = + \frac{1}{2}$

Vedclass · Answer

(B) The electronic configuration of $K$ $(Z = 19)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^1$. The outermost electron is in the $4s$ orbital. For the $4s$ orbital,the principal quantum number $n = 4$. For an $s$-orbital,the azimuthal quantum number $l = 0$. Since $l = 0$,the magnetic quantum number $m = 0$. The spin quantum number $s$ for the single electron in the $4s$ orbital is $+ \frac{1}{2}$. Thus,the set of quantum numbers is $n = 4, l = 0, m = 0, s = + \frac{1}{2}$.

List-$I$ (Orbital)	List-$II$ (Radial nodes and nodal plane)
$A$. $2s$	$I$. $1$ Radial node + two nodal planes
$B$. $3s$	$II$. $1$ Radial node + one nodal plane
$C$. $3p$	$III$. $2$ Radial nodes + No nodal plane
$D$. $4d$	$IV$. $1$ Radial node + No nodal plane

The four quantum numbers of the outermost orbital of $K$ (atomic number $= 19$) are:

Similar Questions

Which one of the following electronic arrangements is absurd?

Select the set of quantum numbers which is $NOT$ associated with any electron in $Cr$ $(Z = 24)$.

Which of the following is the correct electronic configuration of $Cr$ (Chromium)?

Match the $LIST$-$I$ with $LIST$-$II$:
List-$I$ (Orbital) List-$II$ (Radial nodes and nodal plane)
$A$. $2s$ $I$. $1$ Radial node + two nodal planes
$B$. $3s$ $II$. $1$ Radial node + one nodal plane
$C$. $3p$ $III$. $2$ Radial nodes + No nodal plane
$D$. $4d$ $IV$. $1$ Radial node + No nodal plane

The portion of orbital diagrams representing the electronic configuration of certain elements is shown below. Which of them violate Pauli's Exclusion principle?

Vedclass Test Series

Exam Paper Generator

Online Exam Module