The fringe width in Young's double-slit experiment can be increased if we decrease

  • A
    Separation of the slits
  • B
    Distance between the source and the screen
  • C
    Wavelength of the source
  • D
    All of these

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If the distance between the first maxima and the fifth minima of a double slit pattern is $7\,mm$ and the slits are separated by $0.15\,mm$ with the screen $50\,cm$ from the slits,then find the wavelength of the light used in $nm$.

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Two slits are separated by a distance of $0.5\, mm$ and illuminated with light of $\lambda = 6000\ \mathring A$. If the screen is placed $2.5\, m$ from the slits,the distance of the third bright fringe from the centre will be........$mm$.

Given below are two statements. One is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A) :$ In Young's double slit experiment,the fringes produced by red light are closer as compared to those produced by blue light.
Reason $(R) :$ The fringe width is directly proportional to the wavelength of light.
In the light of above statements,choose the correct answer from the options given below $:$

In a Young's double-slit interference experiment,a monochromatic beam of light is used to form fringes on a screen. When a thin mica sheet is placed in the path of one of the interfering beams,then...

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