The function $f(x) = \cot x$ is discontinuous at every point of the set
- A$\{x = 2n\pi ; n \in Z\}$
- B$\{x = (2n+1) \frac{\pi}{2} ; n \in Z\}$
- C$\{x = \frac{n\pi}{2} ; n \in Z\}$
- D$\{x = n\pi ; n \in Z\}$
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Similar Questions
Discuss the continuity of the following functions:
a) $f(x) = \sin x + \cos x$
b) $f(x) = \sin x - \cos x$
c) $f(x) = \sin x \times \cos x$
a) $f(x) = \sin x + \cos x$
b) $f(x) = \sin x - \cos x$
c) $f(x) = \sin x \times \cos x$
Medium
View SolutionSuppose $f(x) = \begin{cases} a + bx, & x < 1 \\ 4, & x = 1 \\ b - ax, & x > 1 \end{cases}$ and if $\lim_{x \to 1} f(x) = f(1)$,what are the possible values of $a$ and $b$?
Easy
View SolutionDiscuss the continuity of the function $f$ given by
$f(x) = \begin{cases} x, & \text{if } x \ge 0 \\ x^2, & \text{if } x < 0 \end{cases}$
$f(x) = \begin{cases} x, & \text{if } x \ge 0 \\ x^2, & \text{if } x < 0 \end{cases}$
Easy
View SolutionThe value of $a$ for which the function $f(x) = \begin{cases} \frac{1-\cos 4 x}{x^2}, & x < 0 \\ a, & x=0 \\ \frac{\sqrt{x}}{\sqrt{16+\sqrt{x}}-4}, & x>0 \end{cases}$ is continuous at $x=0$, is
Which of the following function$(s)$ not defined at $x = 0$ has/have an irremovable discontinuity at $x = 0$?
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