The fusion of chromite ore $(FeCr_{2}O_{4})$ with $Na_{2}CO_{3}$ in air gives a yellow solution upon addition of water. Subsequent treatment with $H_{2}SO_{4}$ produces an orange solution. The yellow and orange colours,respectively,are due to the formation of

  • A
    $Na_{2}CrO_{4}$ and $Na_{2}Cr_{2}O_{7}$
  • B
    $Cr(OH)_{3}$ and $Na_{2}Cr_{2}O_{7}$
  • C
    $Cr_{2}(CO_{3})_{3}$ and $Fe_{2}(SO_{4})_{3}$
  • D
    $Cr(OH)_{3}$ and $Na_{2}CrO_{4}$

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Similar Questions

What is the use of potassium dichromate $(K_2Cr_2O_7)$?

$CrO_3$ is a/an ...

Match the following:
List-$I$List-$II$
$A$. $Co^{2+}$$I$. Yellow colour
$B$. $Fe^{2+}$$II$. Dark green colour
$C$. $Ni^{2+}$$III$. Blue colour
$D$. $Cu^{2+}$$IV$. Pale green colour
$V$. Pink colour

The correct answer is

$A$ group of acidic oxides is

$NaCl$ reacts with conc. $H_2SO_4$ and $K_2Cr_2O_7$ to give reddish fumes $(B)$,which react with $NaOH$ to give yellow solution $(C)$. $(B)$ and $(C)$ respectively are:

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