(C) The concentration of hydrogen ions is given as $[H^{+}] = 0.01 \, mole/litre = 10^{-2} \, mole/litre$.Using the formula for $pH$,we have $pH = -\l

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(C) The concentration of hydrogen ions is given as $[H^{+}] = 0.01 \, mole/litre = 10^{-2} \, mole/litre$.Using the formula for $pH$,we have $pH = -\log[H^{+}]$.Substituting the value,$pH = -\log(10^{-2})$.Applying the logarithmic property $\log(a^b) = b \log(a)$,we get $pH = -(-2) \log(10)$.Since $\log(10) = 1$,the $pH = 2$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)pH of strong Acids and strong Bases

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The gastric juice in our stomach contains enough $HCl$ to make the hydrogen ion concentration about $0.01 \, mole/litre$. The $pH$ of gastric juice is

A
$0.01$
B
$1$
C
$2$
D
$14$

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6-2.Equilibrium-II (Ionic Equilibrium)

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pH of strong Acids and strong Bases

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The gastric juice in our stomach contains enough $HCl$ to make the hydrogen ion concentration about $0.01 \, mole/litre$. The $pH$ of gastric juice is

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