The general solution of $\tan 3x = 1$ is
- A$x = n\pi, n \in Z$
- B$x = n\left(\frac{\pi}{3}\right) + \frac{\pi}{12}, n \in Z$
- C$x = n\pi + \frac{\pi}{4}, n \in Z$
- D$x = n\pi \pm \frac{\pi}{4}, n \in Z$
Explore More
Similar Questions
The sum of the solutions of $\cos x \sqrt{16 \sin ^2 x} = 1$ in $(0, 2 \pi)$ is
If $\tan n\theta = \tan m\theta$,then the different values of $\theta$ will be in
Medium
View SolutionThe set of solutions of the equation $(\sqrt{3}-1) \sin \theta+(\sqrt{3}+1) \cos \theta=2$ is
Find the general solution of the equation $\sin 2x + \cos x = 0$.
Medium
View SolutionThe most general value of $\theta$ which satisfies both the equations $\tan \theta = -1$ and $\cos \theta = \frac{1}{\sqrt{2}}$ is
DifficultTS EAMCET 2011
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo