The general solution of $\tan 3x = 1$ is

Find the general solution of $\csc x = -2$.

The principal solutions of $\cos 2x = -\frac{1}{2}$ are

Solve $\tan 2x = -\cot \left(x + \frac{\pi}{3}\right)$

If ${\left( {\frac{{\sin \theta }}{{\sin \phi }}} \right)^2} = \frac{{\tan \theta }}{{\tan \phi }} = 3,$ then the values of $\theta$ and $\phi$ are:

If $\alpha, \beta, \gamma$ and $\delta$ are the solutions of the equation $\tan \left( \theta + \frac{\pi}{4} \right) = 3 \tan 3\theta$,no two of which have equal tangents,then the value of $\tan \alpha + \tan \beta + \tan \gamma + \tan \delta$ is