The general solution of the trigonometric equ | vedclass

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Question

(A) Given the equation: $	an 	heta = \cot \alpha$ We know that $\cot \alpha = 	an \left( \frac{\pi}{2} - \alpha ight)$. Substituting this into th

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$	heta = n\pi + \frac{\pi}{2} - \alpha$

Vedclass · Answer

(A) Given the equation: $	an 	heta = \cot \alpha$ We know that $\cot \alpha = 	an \left( \frac{\pi}{2} - \alpha ight)$. Substituting this into the equation,we get: $	an 	heta = 	an \left( \frac{\pi}{2} - \alpha ight)$. The general solution for $	an 	heta = 	an \beta$ is $	heta = n\pi + \beta$,where $n \in \mathbb{Z}$. Therefore,the general solution is $	heta = n\pi + \frac{\pi}{2} - \alpha$.

The general solution of the trigonometric equation $\tan \theta = \cot \alpha$ is

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