The general value of theta satisfying the equ | vedclass

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(B) Given the equation: $	an 	heta + 	an \left( \frac{\pi}{2} - 	heta ight) = 2$ Since $	an \left( \frac{\pi}{2} - 	heta ight) = \cot 	heta

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$n\pi + \frac{\pi}{4}$

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(B) Given the equation: $	an 	heta + 	an \left( \frac{\pi}{2} - 	heta ight) = 2$ Since $	an \left( \frac{\pi}{2} - 	heta ight) = \cot 	heta$,the equation becomes: $	an 	heta + \cot 	heta = 2$ $	an 	heta + \frac{1}{	an 	heta} = 2$ Multiplying by $	an 	heta$: $	an^2 	heta - 2 	an 	heta + 1 = 0$ $(	an 	heta - 1)^2 = 0$ $	an 	heta = 1 = 	an \frac{\pi}{4}$ The general solution for $	an 	heta = 	an \alpha$ is $	heta = n\pi + \alpha$. Therefore,$	heta = n\pi + \frac{\pi}{4}$.

The general value of $\theta$ satisfying the equation $\tan \theta + \tan \left( \frac{\pi}{2} - \theta \right) = 2$ is:

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