The geometry around boron in the product '$B$' formed from the following reaction is
$BF_{3} + NaH \xrightarrow{450 \ K} A + NaF$
$A + NMe_{3} \rightarrow B$

  • A
    trigonal planar
  • B
    tetrahedral
  • C
    pyramidal
  • D
    square planar

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