The graph AB shown in the figure is a plot of | vedclass

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(B) The relation between the Celsius $(C)$ and Fahrenheit $(F)$ scales of temperature is given by the formula:$\frac{C}{5} = \frac{F - 32}{9}$Rearrang

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slope of line $AB$ is $5/9$

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(B) The relation between the Celsius $(C)$ and Fahrenheit $(F)$ scales of temperature is given by the formula:$\frac{C}{5} = \frac{F - 32}{9}$Rearranging this equation to express $C$ in terms of $F$:$C = \frac{5}{9}F - \frac{160}{9}$Comparing this with the standard equation of a straight line,$y = mx + c$,where $y$ is the temperature in Celsius,$x$ is the temperature in Fahrenheit,and $m$ is the slope:Here,$y = C$ and $x = F$.Thus,the slope $m = 5/9$.Therefore,the slope of the line $AB$ is $5/9$.

The graph $AB$ shown in the figure is a plot of the temperature of a body in degree Celsius $(C)$ versus degree Fahrenheit $(F)$. Then:

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