The graph below represents a typical stress-strain curve for a metal. Identify the point on the graph that is the ultimate tensile strength of the material.

The stress vs. strain curve for the elastic tissue of the aorta,the large tube (vessel) carrying blood from the heart,will be: [Note: Stress is proportional to the square of the strain for the elastic tissue of the aorta.]

The graph is drawn between the applied force $F$ and the strain $(x)$ for a thin uniform wire. The wire behaves as a liquid in the part:

In the below graph,point $B$ indicates

The diagram below shows the change in the length $X$ of a thin uniform wire caused by the application of stress $F$ at two different temperatures $T_1$ and $T_2$. The variation shown suggests that

Assertion $(A)$: Ductile metals are used to prepare thin wires.
Reason $(R)$: In the stress-strain curve of ductile metals,the length between the points representing elastic limit and breaking point is very small.