The graph of displacement $s$ versus time $t$ is given below. Its corresponding velocity-time graph will be:

The position of a particle related to time is given by $x = (5t^2 - 4t + 5) \, m$. The magnitude of velocity of the particle at $t = 2 \, s$ will be $........... \, ms^{-1}$.

An object at rest at the origin begins to move in the $+x$-direction with a uniform acceleration of $1 \, m/s^2$ for $4 \, s$ and then it continues moving with a uniform velocity of $4 \, m/s$ in the same direction. The $x-t$ graph for the object's motion will be:

From the $v-t$ graph,find the total distance covered by the car in time $t = t_1 + t_2$.

The displacement-time graph for two particles $A$ and $B$ are straight lines inclined at angles of $30^\circ$ and $60^\circ$ with the time axis. The ratio of velocities $V_A:V_B$ is

The position $x$ of a particle varies with time $t$ as $x = ct^2 + b$,where $c$ and $b$ are positive constants. Which of the following graphs is correct?