The graph of linear polynomial p(x) = 3x - 6 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To find the point where the graph of the polynomial $p(x) = 3x - 6$ intersects the $X$-axis,we set $p(x) = 0$.Setting the polynomial to zero gives

Vedclass · Accepted Answer

$(2, 0)$

Vedclass · Answer

(D) To find the point where the graph of the polynomial $p(x) = 3x - 6$ intersects the $X$-axis,we set $p(x) = 0$.Setting the polynomial to zero gives: $3x - 6 = 0$.Adding $6$ to both sides: $3x = 6$.Dividing by $3$: $x = 2$.Since the point lies on the $X$-axis,its $y$-coordinate is $0$.Therefore,the graph intersects the $X$-axis at the point $(2, 0)$.

The graph of linear polynomial $p(x) = 3x - 6$ intersects the $X$-axis at $\ldots......$

Similar Questions

$(x+1)$ is not one of the factors of .........

Prove that $-2$,$4$,and $\frac{1}{2}$ are the zeros of the cubic polynomial $p(x) = 2x^3 - 5x^2 - 14x + 8$. Also,verify the relationship between the zeros and the coefficients.

State the degree of the given polynomial: $p(x) = 5x - 2x^2 + 3$

The zeros of $p(x) = 3x^2 - x - 4$ are $\alpha$ and $\beta$,then $\alpha^2 \beta + \alpha \beta^2 = \ldots$

Find the zeros of the following quadratic polynomial: $p(x) = 4x^2 - 256$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module