The graph of stopping potential $(V_{s})$ against frequency $(\nu)$ of incident radiation is plotted for two different metals '$P$' and '$Q$' as shown in the graph. If $\phi_{P}$ and $\phi_{Q}$ are the work functions of metals '$P$' and '$Q$' respectively,then which of the following is correct?

  • A
    $\phi_{P} = \phi_{Q}$
  • B
    $\nu_{0} < \nu_{0}^{\prime}$
  • C
    $\phi_{P} < \phi_{Q}$
  • D
    $\phi_{P} > \phi_{Q}$

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