The graph of the equation x+y=11 passes throu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The equation is $x+y=11$.
To find the quadrants,we check the intercepts:
If $x=0$,then $y=11$. The point is $(0, 11)$,which lies on the $y$-axis

Vedclass · Accepted Answer

fourth and second quadrants

Vedclass · Answer

(B) The equation is $x+y=11$. To find the quadrants,we check the intercepts: If $x=0$,then $y=11$. The point is $(0, 11)$,which lies on the $y$-axis between the first and second quadrants. If $y=0$,then $x=11$. The point is $(11, 0)$,which lies on the $x$-axis between the first and fourth quadrants. Since the line passes through $(0, 11)$ and $(11, 0)$,it passes through the first quadrant (where $x>0, y>0$),the second quadrant (where $x<0, y>0$ for $x < 0$),and the fourth quadrant (where $x>0, y<0$ for $x > 11$). Thus,the line passes through the second,first,and fourth quadrants.

The graph of the equation $x+y=11$ passes through the first quadrant and .............

Similar Questions

Express the following linear equation in the form $ax + by + c = 0$ and indicate the values of $a, b$ and $c$ in each case: $6x - 5y = 4.2\overline{7}$

Write four solutions for the following equation: $4x - 3y = 24$.

At what point does the graph of the linear equation $x+y=5$ meet a line which is parallel to the $y$-axis,at a distance $2$ units from the origin and in the positive direction of the $x$-axis?

Solve the equation $3x - 1 = x + 7$ and represent the solution$(s)$ on $(1)$ the number line $(2)$ the Cartesian plane.

If $(3, 2)$ is one of the solutions of $5x - ay = 7$,then $a = \dots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module