The graph shows the variation of voltage (V) | vedclass

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(B) The relationship between charge $(Q)$,voltage $(V)$,and capacitance $(C)$ is given by $Q = CV$,which can be rearranged as $V = Q/C$.In the given g

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capacity of $A$ is higher than $B$.

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(B) The relationship between charge $(Q)$,voltage $(V)$,and capacitance $(C)$ is given by $Q = CV$,which can be rearranged as $V = Q/C$.In the given graph,voltage $(V)$ is plotted on the $y$-axis and charge $(Q)$ is plotted on the $x$-axis.The slope of this graph is $V/Q = 1/C$.From the graph,for a fixed charge $Q$,the voltage $V_B > V_A$.Since the slope is inversely proportional to capacitance $(C)$,a higher slope corresponds to a lower capacitance.Therefore,the slope of line $B$ is greater than the slope of line $A$,which implies that the capacitance of $A$ is greater than the capacitance of $B$ $(C_A > C_B)$.

The graph shows the variation of voltage $(V)$ across the plates of two parallel plate capacitors $A$ and $B$ versus the charge $(Q)$ stored in them. Then

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