The gravitational force between a H-atom and | vedclass

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(B) According to Einstein's mass-energy equivalence principle,the mass of a bound system is less than the sum of the masses of its constituents by an

Vedclass · Accepted Answer

$M = m_{proton} + m_{electron} - \frac{B}{c^2}$ (where $B = 13.6 \, eV$)

Vedclass · Answer

(B) According to Einstein's mass-energy equivalence principle,the mass of a bound system is less than the sum of the masses of its constituents by an amount equal to the binding energy divided by $c^2$.For a hydrogen atom,the total mass $M$ is given by $M = m_{proton} + m_{electron} - \frac{B}{c^2}$,where $B$ is the binding energy of the hydrogen atom $(13.6 \, eV)$.This mass defect accounts for the energy released during the formation of the atom from its constituents.

The gravitational force between a $H$-atom and another particle of mass $m$ is given by Newton's law $F = G\frac{M m}{r^2}$. Here,$M$ represents:

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