The gravitational force between two stones of | vedclass

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Question

(C) According to Newton's law of universal gravitation,the force $F$ between two masses $m_1$ and $m_2$ separated by a distance $r$ is given by $F = G

Vedclass · Accepted Answer

$6.675 	imes 10^{-11} \, N$

Vedclass · Answer

(C) According to Newton's law of universal gravitation,the force $F$ between two masses $m_1$ and $m_2$ separated by a distance $r$ is given by $F = G \frac{m_1 m_2}{r^2}$.Given: $m_1 = 1 \, kg$,$m_2 = 1 \, kg$,$r = 1 \, m$,and the gravitational constant $G = 6.675 	imes 10^{-11} \, N \cdot m^2/kg^2$.Substituting these values into the formula:$F = (6.675 	imes 10^{-11}) 	imes \frac{1 	imes 1}{1^2} = 6.675 	imes 10^{-11} \, N$.

The gravitational force between two stones of mass $1 \, kg$ each,separated by a distance of $1 \, m$ in a vacuum,is:

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