The grid in a triode valve is used

  • A
    To increase the thermionic emission
  • B
    To control the plate to cathode current
  • C
    To reduce the inter-electrode capacity
  • D
    To keep cathode at constant potential

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When the plate voltage in a diode valve is increased from $100 \, V$ to $150 \, V$, the plate current increases from $7.5 \, mA$ to $12 \, mA$. The dynamic plate resistance will be.... $k \, \Omega$.

In the grid circuit of a triode, an input voltage $E = 2\sqrt{2} \cos \omega t$ is applied. If the amplification factor $\mu = 14$ and the plate resistance $r_p = 10 \text{ k}\Omega$, find the $r.m.s.$ current flowing through the load resistance $R_L = 12 \text{ k}\Omega$ in $\text{mA}$.

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In an amplifier,the load resistance ${R_L}$ is equal to the plate resistance ${r_p}$. The voltage amplification is equal to:

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