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Question

(A) The $CO$ molecule has a total of $14$ electrons ($6$ from $C$ and $8$ from $O$).According to Molecular Orbital Theory, for molecules with $14$ or

Vedclass · Accepted Answer

$1 \sigma^{2} 2 \sigma^{2} 1 \pi^{4} 3 \sigma^{2}$

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(A) The $CO$ molecule has a total of $14$ electrons ($6$ from $C$ and $8$ from $O$).According to Molecular Orbital Theory, for molecules with $14$ or fewer electrons, the energy order of molecular orbitals is $\sigma 1s Filling the $14$ electrons into these orbitals:$1\sigma^2, 2\sigma^2, 3\sigma^2, 4\sigma^2, 1\pi^4, 5\sigma^2$.In many textbooks, the notation is simplified as $1\sigma^2 2\sigma^2 1\pi^4 3\sigma^2$ where $1\sigma$ is $\sigma 1s$, $2\sigma$ is $\sigma^* 1s$, $3\sigma$ is $\sigma 2s$, $4\sigma$ is $\sigma^* 2s$, $1\pi$ is $\pi 2p$, and $5\sigma$ is $\sigma 2p_z$.Thus, the correct configuration is $1\sigma^2 2\sigma^2 3\sigma^2 4\sigma^2 1\pi^4 5\sigma^2$, which corresponds to option $A$ when simplified.

The ground state electronic configuration of $CO$ molecule is

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