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(C) The energy of an electron in a hydrogen-like species is given by the formula: $E_n = -13.6 	imes \frac{Z^2}{n^2} \ eV$.For the $He^{+}$ ion,the a

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$-6.04$

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(C) The energy of an electron in a hydrogen-like species is given by the formula: $E_n = -13.6 	imes \frac{Z^2}{n^2} \ eV$.For the $He^{+}$ ion,the atomic number $Z = 2$.The ground state is $n = 1$,the first excited state is $n = 2$,and the second excited state is $n = 3$.Substituting $Z = 2$ and $n = 3$ into the formula:$E_3 = -13.6 	imes \frac{2^2}{3^2} \ eV$$E_3 = -13.6 	imes \frac{4}{9} \ eV$$E_3 = -13.6 	imes 0.4444 \ eV = -6.04 \ eV$.

The ground state energy of hydrogen atom is $-13.6 \ eV$. The energy of the second excited state of $He^{+}$ ion in $eV$ is:

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