The group 14 elements A and B have the first | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In group $14$,the first ionisation enthalpy decreases down the group due to the increase in atomic size,but $Pb$ shows a higher value than $Sn$ du

Vedclass · Accepted Answer

reducing and oxidising

Vedclass · Answer

(C) In group $14$,the first ionisation enthalpy decreases down the group due to the increase in atomic size,but $Pb$ shows a higher value than $Sn$ due to the inert pair effect and poor shielding of $4f$ electrons. Given the values,$A$ corresponds to $Sn$ $(708 \ kJ \ mol^{-1})$ and $B$ corresponds to $Pb$ $(715 \ kJ \ mol^{-1})$. $Sn^{2+}$ acts as a reducing agent because it tends to get oxidised to $Sn^{4+}$,which is the more stable oxidation state for $Sn$. $Pb^{4+}$ acts as an oxidising agent because it tends to get reduced to $Pb^{2+}$,which is the more stable oxidation state for $Pb$ due to the inert pair effect. Therefore,$A^{2+}$ is reducing and $B^{4+}$ is oxidising.

The group $14$ elements $A$ and $B$ have the first ionisation enthalpy values of $708$ and $715 \ kJ \ mol^{-1}$ respectively. These values are the lowest among their group members. The nature of their ions $A^{2+}$ and $B^{4+}$ respectively is:

Similar Questions

What would be the major product of the following reaction: $SiCl_4 \xrightarrow{\text{Excess of } H_2O}$?

Davy and Faraday proved that

$SiO_{2}$ is attacked by which of the following?

The number of six-membered and five-membered rings in Buckminster fullerene respectively is

Which of the following oxides is amphoteric?

Vedclass Test Series

Exam Paper Generator

Online Exam Module