The gyromagnetic ratio of an electron revolvi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The gyromagnetic ratio is defined as the ratio of the magnetic dipole moment to the angular momentum of the electron,which is given by the formula

Vedclass · Accepted Answer

$ \frac{1}{11} 	imes 10^{-29} \ kg $

Vedclass · Answer

(D) The gyromagnetic ratio is defined as the ratio of the magnetic dipole moment to the angular momentum of the electron,which is given by the formula: $\gamma = \frac{e}{2m_e}$.Given,gyromagnetic ratio $\gamma = 8.8 	imes 10^{10} \ C \ kg^{-1}$.Charge of the electron $e = 1.6 	imes 10^{-19} \ C$.Rearranging the formula to solve for the mass of the electron $m_e$:$m_e = \frac{e}{2\gamma}$.Substituting the given values:$m_e = \frac{1.6 	imes 10^{-19}}{2 	imes 8.8 	imes 10^{10}}$.$m_e = \frac{1.6 	imes 10^{-19}}{17.6 	imes 10^{10}}$.$m_e = \frac{16}{176} 	imes 10^{-29} \ kg$.$m_e = \frac{1}{11} 	imes 10^{-29} \ kg$.Thus,the mass of the electron is $\frac{1}{11} 	imes 10^{-29} \ kg$.

The gyromagnetic ratio of an electron revolving in a circular orbit of a hydrogen atom is $ 8.8 \times 10^{10} \ C \ kg^{-1} $. What is the mass of the electron? Given the charge of the electron $ e = 1.6 \times 10^{-19} \ C $.

Similar Questions

The magnetic moment $(\mu)$ of a revolving electron around the nucleus varies with principal quantum number $n$ as

Explain orbital magnetic moment and spin magnetic moment.

$A$ proton moves on a circular path with a constant angular speed. What is the correct relation between its magnetic moment $\vec{M}$ and angular momentum $\vec{L}$?

If $M_0$ and $L_0$ denote the magnetic moment and angular momentum of the electron due to its orbital motion respectively,then the gyromagnetic ratio is given by

If the charge to mass ratio of an electron is $A \ C/kg$,then the gyromagnetic ratio of an orbital electron in $C/kg$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module