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(D) Given half-life $T_{1/2} = 12 	ext{ minutes}$.At $28 \%$ decay, the remaining amount is $100 - 28 = 72 \%$.At $82 \%$ decay, the remaining amount

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$24 	ext{ minutes}$

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(D) Given half-life $T_{1/2} = 12 	ext{ minutes}$.At $28 \%$ decay, the remaining amount is $100 - 28 = 72 \%$.At $82 \%$ decay, the remaining amount is $100 - 82 = 18 \%$.We know that the amount of radioactive substance reduces to half in one half-life period.Starting from $72 \%$, after one half-life $(12 	ext{ minutes})$, the amount becomes $72 / 2 = 36 \%$.After another half-life $(12 	ext{ minutes})$, the amount becomes $36 / 2 = 18 \%$.Therefore, the total time gap is $12 + 12 = 24 	ext{ minutes}$.

The half-life of a radioactive substance is $12 \text{ minutes}$. The time gap between $28 \%$ decay and $82 \%$ decay of the radioactive substance is

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