The heat of combustion of CH_{4(g)},C_{(graph | vedclass

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(C) The combustion reactions are given as follows:$I. CH_{4(g)} + 2O_{2(g)} 	o CO_{2(g)} + 2H_2O_{(l)}, \Delta H_1 = -20 \ kcal$$II. C_{(graphite)} +

Vedclass · Accepted Answer

$-80$

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(C) The combustion reactions are given as follows:$I. CH_{4(g)} + 2O_{2(g)} 	o CO_{2(g)} + 2H_2O_{(l)}, \Delta H_1 = -20 \ kcal$$II. C_{(graphite)} + O_{2(g)} 	o CO_{2(g)}, \Delta H_2 = -40 \ kcal$$III. H_{2(g)} + \frac{1}{2}O_{2(g)} 	o H_2O_{(l)}, \Delta H_3 = -10 \ kcal$We need to find the heat of formation of methane,which corresponds to the reaction:$C_{(graphite)} + 2H_{2(g)} 	o CH_{4(g)}, \Delta H_f = ?$Using Hess's Law,we perform the operation: $II + 2 	imes III - I$$\Delta H_f = \Delta H_2 + 2(\Delta H_3) - \Delta H_1$$\Delta H_f = -40 + 2(-10) - (-20)$$\Delta H_f = -40 - 20 + 20 = -40 \ kcal$Note: The provided options do not contain the correct result $-40 \ kcal$. Based on the calculation,the correct value is $-40 \ kcal$.

The heat of combustion of $CH_{4(g)}$,$C_{(graphite)}$ and $H_{2(g)}$ are $-20 \ kcal$,$-40 \ kcal$ and $-10 \ kcal$ respectively. The heat of formation of methane is.......$kcal$.

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