The heat radiated per unit area in 1,hour by | vedclass

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(A) According to $Stefan's\,law$, the power radiated per unit area is given by $E = \sigma T^4$.Given:Temperature $T = 3000\,K$Stefan's constant $\sig

Vedclass · Accepted Answer

$1.7 	imes 10^{10}\,J$

Vedclass · Answer

(A) According to $Stefan's\,law$, the power radiated per unit area is given by $E = \sigma T^4$.Given:Temperature $T = 3000\,K$Stefan's constant $\sigma = 5.7 	imes 10^{-8}\,W\,m^{-2}\,K^{-4}$Time $t = 1\,hour = 3600\,s$The heat radiated per unit area $(Q/A)$ in time $t$ is:$Q/A = E 	imes t = \sigma T^4 	imes t$Substituting the values:$Q/A = (5.7 	imes 10^{-8}) 	imes (3000)^4 	imes 3600$$Q/A = 5.7 	imes 10^{-8} 	imes 81 	imes 10^{12} 	imes 3600$$Q/A = 5.7 	imes 81 	imes 3600 	imes 10^4$$Q/A = 1662120 	imes 10^4 = 1.66212 	imes 10^{10}\,J \approx 1.7 	imes 10^{10}\,J$.

The heat radiated per unit area in $1\,hour$ by a furnace whose temperature is $3000\,K$ is $(\sigma = 5.7 \times 10^{-8}\,W\,m^{-2}\,K^{-4})$.

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