The heating of (NH_4)_2Cr_2O_7 produces anoth | vedclass

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(D) The heating of $(NH_4)_2Cr_2O_7$ produces $Cr_2O_3$ compound along with $N_2$ gas.$(NH_4)_2Cr_2O_7 \stackrel{\Delta}{\longrightarrow} N_2 + Cr_2O_

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$+6$ to $+3$

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(D) The heating of $(NH_4)_2Cr_2O_7$ produces $Cr_2O_3$ compound along with $N_2$ gas.$(NH_4)_2Cr_2O_7 \stackrel{\Delta}{\longrightarrow} N_2 + Cr_2O_3 + 4H_2O$Let the oxidation state of $Cr$ be $x$.In $(NH_4)_2Cr_2O_7$:$2(+1) + 2(x) + 7(-2) = 0$$2 + 2x - 14 = 0$$2x = 12 \Rightarrow x = +6$In $Cr_2O_3$:$2(x) + 3(-2) = 0$$2x - 6 = 0$$2x = 6 \Rightarrow x = +3$Therefore,the change in the oxidation state of $Cr$ in the reaction is from $+6$ to $+3$.

The heating of $(NH_4)_2Cr_2O_7$ produces another chromium compound along with $N_2$ gas. The change of the oxidation state of $Cr$ in the reaction is

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