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Question

(D) The maximum line-of-sight distance $d$ between a transmitting antenna of height $h_T$ and a receiving antenna of height $h_R$ is given by the form

Vedclass · Accepted Answer

$192$

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(D) The maximum line-of-sight distance $d$ between a transmitting antenna of height $h_T$ and a receiving antenna of height $h_R$ is given by the formula:$d = \sqrt{2 R h_T} + \sqrt{2 R h_R}$Given:$h_T = 25 \; m$$h_R = 49 \; m$$R = 64 	imes 10^{5} \; m$Substituting the values:$d = \sqrt{2 	imes 64 	imes 10^{5} 	imes 25} + \sqrt{2 	imes 64 	imes 10^{5} 	imes 49}$$d = \sqrt{2 	imes 64 	imes 10^{5}} 	imes (\sqrt{25} + \sqrt{49})$$d = \sqrt{128 	imes 10^{5}} 	imes (5 + 7)$$d = \sqrt{1280 	imes 10^{4}} 	imes 12$$d = \sqrt{256 	imes 5 	imes 10^{4}} 	imes 12$$d = (16 	imes 10^{2} \sqrt{5}) 	imes 12$$d = 192 \sqrt{5} 	imes 10^{2} \; m$Comparing this with $K \sqrt{5} 	imes 10^{2} \; m$,we get $K = 192$.

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