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(D) The maximum line-of-sight distance $d_{\max}$ between a transmitting antenna of height $h_t$ and a receiving antenna of height $h_r$ is given by t

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$104$

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(D) The maximum line-of-sight distance $d_{\max}$ between a transmitting antenna of height $h_t$ and a receiving antenna of height $h_r$ is given by the formula:$d_{\max} = \sqrt{2Rh_t} + \sqrt{2Rh_r}$Given:$R = 6400\,km = 64 	imes 10^5\,m$$h_t = 180\,m$$h_r = 245\,m$Substituting the values:$d_{\max} = \sqrt{2 	imes 64 	imes 10^5 	imes 180} + \sqrt{2 	imes 64 	imes 10^5 	imes 245}$$d_{\max} = \sqrt{128 	imes 180 	imes 10^5} + \sqrt{128 	imes 245 	imes 10^5}$$d_{\max} = \sqrt{23040 	imes 10^5} + \sqrt{31360 	imes 10^5}$$d_{\max} = \sqrt{2304 	imes 10^6} + \sqrt{3136 	imes 10^6}$$d_{\max} = (48 	imes 10^3) + (56 	imes 10^3)\,m$$d_{\max} = 48\,km + 56\,km = 104\,km$.

The height of the transmitting antenna is $180\,m$ and the height of the receiving antenna is $245\,m$. The maximum distance between them for satisfactory communication in line of sight will be .......... $km$ (given $R = 6400\,km$).

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