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(C) The maximum line-of-sight distance $d$ between a transmitting antenna of height $h_T$ and a receiving antenna of height $h_R$ is given by the form

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$49.6$

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(C) The maximum line-of-sight distance $d$ between a transmitting antenna of height $h_T$ and a receiving antenna of height $h_R$ is given by the formula: $d = \sqrt{2 R h_T} + \sqrt{2 R h_R}$.Given: $h_T = 33.8 \ m = 33.8 	imes 10^{-3} \ km$,$h_R = 64.8 \ m = 64.8 	imes 10^{-3} \ km$,and $R = 6400 \ km$.Substituting the values:$d = \sqrt{2 	imes 6400 	imes 33.8 	imes 10^{-3}} + \sqrt{2 	imes 6400 	imes 64.8 	imes 10^{-3}}$$d = \sqrt{12800 	imes 0.0338} + \sqrt{12800 	imes 0.0648}$$d = \sqrt{432.64} + \sqrt{829.44}$$d = 20.8 \ km + 28.8 \ km = 49.6 \ km$.

$List-I$	$List-II$
$A.$ Facsimile	$I.$ Static Document Image
$B.$ Guided media Channel	$II.$ Local Broadcast Radio
$C.$ Frequency Modulation	$III.$ Rectangular wave
$D.$ Digital Signal	$IV.$ Optical Fiber

The heights of the transmitting and receiving antennas are $33.8 \ m$ and $64.8 \ m$ respectively. The maximum distance between the antennas for satisfactory communication in a line of sight mode is (Radius of the earth $= 6400 \ km$) (in $km$)

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$List-I$ $List-II$
$A.$ Facsimile $I.$ Static Document Image
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