The higher oxidation states of transition ele | vedclass

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Question

(A) The higher oxidation states of transition elements are found in combination with $F$ and $O$ because $F$ and $O$ are the most electronegative elem

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$F, O$

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(A) The higher oxidation states of transition elements are found in combination with $F$ and $O$ because $F$ and $O$ are the most electronegative elements.These elements have a high ability to stabilize the higher oxidation states of transition metals.For example,$Os$ shows the highest oxidation state of $+8$ in $OsO_4$.Similarly,$Mn$ shows the highest oxidation state of $+7$ in $KMnO_4$.

List-$I$ Species	List-$II$ Electronic distribution
$A$. $Cr^{2+}$	$I$. $3d^8$
$B$. $Mn^{+}$	$II$. $3d^3 4s^1$
$C$. $Ni^{2+}$	$III$. $3d^4$
$D$. $V^{+}$	$IV$. $3d^5 4s^1$

The higher oxidation states of transition elements are found to be in combination with $A$ and $B$,which are:

Similar Questions

Match List-$I$ with List-$II$

List-$I$ Species List-$II$ Electronic distribution

$A$. $Cr^{2+}$ $I$. $3d^8$

$B$. $Mn^{+}$ $II$. $3d^3 4s^1$

$C$. $Ni^{2+}$ $III$. $3d^4$

$D$. $V^{+}$ $IV$. $3d^5 4s^1$

Choose the correct answer from the options given below:

Which of the following is not a representative element?

The number of $d$-electrons in $Cr^{3+}$ ion $(Z=24)$ is

Which of the following rules must be followed to form an alloy?

Why is $_{21}Sc$ not considered a transition element?

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