The highest oxidation state of manganese in fluorides is $+4$ $(MnF_4)$, but the highest oxidation state in oxides is $+7$ $(Mn_2O_7)$, because

  • A
    Fluorine is more electronegative than oxygen
  • B
    Fluorine possesses d-orbitals
  • C
    Fluorine stabilises lower oxidation state
  • D
    In covalent compounds, fluorine can form single bond only, while oxygen forms double bond

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Similar Questions

Which of the following represents the correct chemical reactions related to iron and its compounds?

In which of the following, ions are correctly arranged in the increasing order of oxidizing power?

$(a)$ Transition metals can act as catalysts because they can change their oxidation state. How does $Fe(III)$ catalyze the reaction between iodide and persulphate ions?
$(b)$ Mention any three processes where transition metals act as catalysts.

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View Solution

Assertion : Transition metals are good catalysts.
Reason : $V_2O_5$ or $Pt$ is used in the preparation of $H_2SO_4$ by contact process.

Assertion : $PbI_4, BiCl_5, FeI_3, CuI_2$ do not exist. Reason : Higher oxidation states of metal ions are strong oxidising agents which give redox reactions with the iodide ion.

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