The hybrid state of sulphur in SO_3 molecule | vedclass

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(D) The hybridization of the central atom can be calculated using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the number of valence ele

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$sp^2$

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(D) The hybridization of the central atom can be calculated using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $SO_3$,the central atom is $S$ (valence electrons $V = 6$). Oxygen is a divalent atom,so $M = 0$.$H = \frac{1}{2}(6 + 0 - 0 + 0) = 3$.$A$ value of $H = 3$ corresponds to $sp^2$ hybridization.Thus,the $S$ atom in $SO_3$ is $sp^2$ hybridized,resulting in a trigonal planar structure.

The hybrid state of sulphur in $SO_3$ molecule is

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