The hybridisation in BF_3 molecule is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the $BF_3$ molecule,the central Boron atom has $3$ valence electrons. It forms $3$ single bonds with $3$ Fluorine atoms. Using the formula for

Vedclass · Accepted Answer

$sp^2$

Vedclass · Answer

(B) In the $BF_3$ molecule,the central Boron atom has $3$ valence electrons. It forms $3$ single bonds with $3$ Fluorine atoms. Using the formula for steric number: $	ext{Steric Number} = \frac{1}{2} 	imes (V + M - C + A)$,where $V = 3$ (valence electrons of $B$),$M = 3$ (monovalent atoms),$C = 0$,and $A = 0$. $	ext{Steric Number} = \frac{1}{2} 	imes (3 + 3) = 3$. $A$ steric number of $3$ corresponds to $sp^2$ hybridisation.

The hybridisation in $BF_3$ molecule is

Similar Questions

Among the following compounds,the one that is polar and has a central atom with $sp^2$ hybridization is:

The percentage of $s$-character in the hybrid orbitals of nitrogen in $NO_{2}^{+}$ and $NO_{3}^{-}$ respectively are:

The hybridisation of $Xe$ and the number of lone pairs of electrons on it in $XeF_6$ are

Which type of hybridisation occurs in ethylene?

What are the hybridization type and molecular shape of the central atom in $BrF_5$,respectively?

Vedclass Test Series

Exam Paper Generator

Online Exam Module