The hybridisation of the central atom I in IF | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the molecule $IF_7$,the central atom $I$ (Iodine) has $7$ valence electrons. All $7$ valence electrons are involved in forming $7$ sigma bonds

Vedclass · Accepted Answer

$sp^3d^3$

Vedclass · Answer

(D) In the molecule $IF_7$,the central atom $I$ (Iodine) has $7$ valence electrons. All $7$ valence electrons are involved in forming $7$ sigma bonds with $7$ fluorine atoms. The steric number is calculated as: $	ext{Steric Number} = 	ext{Number of sigma bonds} + 	ext{Number of lone pairs} = 7 + 0 = 7$. $A$ steric number of $7$ corresponds to $sp^3d^3$ hybridization. The geometry and shape of $IF_7$ is pentagonal bipyramidal,where $5$ $F$ atoms are in the equatorial plane and $2$ $F$ atoms are in the axial positions.

The hybridisation of the central atom $I$ in $IF_7$ is:

Similar Questions

Which of the following conversions involves a change in both shape and hybridisation?

Sulphur trioxide is dissolved in heavy water to form a compound $X$. The hybridisation state of sulphur in $X$ is :

What is the $s$-character content in an $sp^3$ hybrid orbital?

Which one of the following pairs is isostructural ($i.e.$,having the same shape and hybridization)?

The correct order regarding electronegativity of hybrid orbitals of carbon is

Vedclass Test Series

Exam Paper Generator

Online Exam Module