The hybridizations of C_2 and C_3 in the mole | vedclass

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(B) In the molecule $H_3C-CH=C=CH-CH_3$,let us number the carbon atoms from left to right: $C_1(H_3)-C_2(H)=C_3=C_4(H)-C_5(H_3)$.$C_2$ is bonded to on

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$sp^2, sp$

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(B) In the molecule $H_3C-CH=C=CH-CH_3$,let us number the carbon atoms from left to right: $C_1(H_3)-C_2(H)=C_3=C_4(H)-C_5(H_3)$.$C_2$ is bonded to one hydrogen atom,one carbon atom via a single bond,and one carbon atom via a double bond. It has $3$ sigma bonds and $0$ lone pairs,resulting in $sp^2$ hybridization.$C_3$ is bonded to two carbon atoms via double bonds on both sides. It has $2$ sigma bonds and $0$ lone pairs,resulting in $sp$ hybridization.Therefore,the hybridizations of $C_2$ and $C_3$ are $sp^2$ and $sp$ respectively.

The hybridizations of $C_2$ and $C_3$ in the molecule $H_3C-CH=C=CH-CH_3$ are respectively:

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