The hybridizations of carbon in graphite,diam | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Diamond,graphite,and $C_{60}$ are allotropes of carbon. In diamond,each carbon atom is bonded to four other carbon atoms in a tetrahedral geometry

Vedclass · Accepted Answer

$sp^2, sp^3, sp^2$

Vedclass · Answer

(B) Diamond,graphite,and $C_{60}$ are allotropes of carbon. In diamond,each carbon atom is bonded to four other carbon atoms in a tetrahedral geometry,resulting in $sp^3$ hybridization. In graphite,each carbon atom is bonded to three other carbon atoms in a planar hexagonal network,resulting in $sp^2$ hybridization. In $C_{60}$ (buckminsterfullerene),each carbon atom is also bonded to three other carbon atoms in a spherical structure,resulting in $sp^2$ hybridization. Therefore,the hybridizations are $sp^2, sp^3, sp^2$ respectively.

The hybridizations of carbon in graphite,diamond and $C_{60}$ are respectively

Similar Questions

The shape of $CH_3^+$ species is

In $sp$ hybridisation,the shape is:

What is $sp$ hybridization? Give its characteristics.

If pure unhybridised orbitals are used in forming $CH_4$ then which statement is incorrect :-

Which of the following molecules is an example of $sp$ hybridization?

Vedclass Test Series

Exam Paper Generator

Online Exam Module