The hydrogen ion concentration of $0.001 \ M$ $NaOH$ solution is
- A$1 \times 10^{-2} \ \text{mole/litre}$
- B$1 \times 10^{-11} \ \text{mole/litre}$
- C$1 \times 10^{-14} \ \text{mole/litre}$
- D$1 \times 10^{-12} \ \text{mole/litre}$
Explore More
Similar Questions
$L$ litres of water must be added to $1 \, L$ of an aqueous solution of $HCl$ with a $pH$ of $1$ to create an aqueous solution with $pH$ of $2$?
DifficultJEE MAIN 2013
View SolutionGiven that the dissociation constant for $H_2O$ is $K_w = 1 \times 10^{-14} \ mol^2 \ L^{-2}$,what is the $pH$ of a $0.001 \ M \ KOH$ solution?
Difficult
View SolutionAn aqueous solution of $HCl$ with $pH \ 1.0$ is diluted by adding an equal volume of water (ignoring the dissociation of water). The $pH$ of the $HCl$ solution would be (Given $\log 2 = 0.30$):
When equal volumes of solutions with $pH = 6$ and $pH = 3$ are mixed,what is the $pH$ of the resulting solution?
Medium
View SolutionWhat is the $pH$ of $10^{-9} \ M$ aqueous $HCl$ solution?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo