The incorrect order of bond angle is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $XeF_2$ has a linear geometry with a bond angle of $180^{\circ}$.$BeF_3^-$,$BF_3$,and $CH_3^+$ are all $sp^2$ hybridized with $0$ lone pairs,resul

Vedclass · Accepted Answer

$PH_3 > PCl_3$

Vedclass · Answer

(D) $XeF_2$ has a linear geometry with a bond angle of $180^{\circ}$.$BeF_3^-$,$BF_3$,and $CH_3^+$ are all $sp^2$ hybridized with $0$ lone pairs,resulting in a bond angle of $120^{\circ}$.$CH_4$,$SiCl_4$,and $BF_4^-$ are all $sp^3$ hybridized with $0$ lone pairs,resulting in a bond angle of $109.5^{\circ}$.$CCl_4$ has a bond angle of $109.5^{\circ}$ and $H_2O$ has a bond angle of $104.5^{\circ}$.In $PH_3$ and $PCl_3$,the bond angle depends on the electronegativity of the central atom and the surrounding atoms. $PH_3$ has a bond angle of $\approx 93^{\circ}$ and $PCl_3$ has a bond angle of $\approx 100^{\circ}$.Therefore,the order $PH_3 > PCl_3$ is incorrect.

Similar Questions

The number of lone pairs of electrons on the central $I$ atom in $I_{3}^{-}$ is $.......$

Molecular shapes of $SF_4$,$CF_4$ and $XeF_4$ are

In the following reaction,how do the $Cl-P-Cl$ bond angles change?
$PCl_5 \longrightarrow PCl_4^+ + Cl^-$

To which type does $ClF_3$ belong among $AB_4$,$AB_4E$,and $AB_3E_2$? Explain.

Which of the following species are planar?

Vedclass Test Series

Exam Paper Generator

Online Exam Module