The incorrect statement regarding 15^{th} gro | vedclass

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(C) $1$. Thermal stability decreases down the group as the $E-H$ bond length increases and bond dissociation enthalpy decreases. Thus,$NH_3 > PH_3 > A

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$NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3$ : Reducing character

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(C) $1$. Thermal stability decreases down the group as the $E-H$ bond length increases and bond dissociation enthalpy decreases. Thus,$NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3$ is correct.$2$. $E-H$ bond dissociation enthalpy decreases down the group due to increasing bond length. Thus,$NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3$ is correct.$3$. Reducing character is inversely proportional to $E-H$ bond dissociation enthalpy. Since $Bi-H$ bond is weakest,$BiH_3$ is the strongest reducing agent. The correct order is $NH_3 $4$. Basicity decreases down the group because the electron density on the central atom decreases as the size of the atom increases. Thus,$NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3$ is correct.

The incorrect statement regarding $15^{th}$ group hydrides $(EH_3)$ where $E = N, P, As, Sb, Bi$ is:

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