The increasing order (lowest first) for the v | vedclass

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(D) The $e/m$ ratio (specific charge) is calculated as follows:$(I)$ For neutron $(n)$: Charge = $0$,Mass = $1$,so $e/m = 0/1 = 0$.$(II)$ For $\alpha$

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$n, \alpha, p, e$

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(D) The $e/m$ ratio (specific charge) is calculated as follows:$(I)$ For neutron $(n)$: Charge = $0$,Mass = $1$,so $e/m = 0/1 = 0$.$(II)$ For $\alpha$-particle $(\alpha)$: Charge = $ 2$,Mass = $4$,so $e/m = 2/4 = 0.5$.$(III)$ For proton $(p)$: Charge = $ 1$,Mass = $1$,so $e/m = 1/1 = 1$.$(IV)$ For electron $(e)$: Charge = $-1$,Mass = $1/1837$,so $e/m = 1/(1/1837) = 1837$.Comparing these values: $0 Therefore,the increasing order is $n < \alpha < p < e$.

The increasing order (lowest first) for the values of $e/m$ (charge/mass) for:

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