The increasing order for the values of e/m (t | vedclass

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(D) The $e/m$ ratio is defined as the charge-to-mass ratio of a particle.For a neutron $(n)$,the charge is $0$,so $e/m = 0$.For an alpha particle $(\a

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$n, \alpha, p, e$

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(D) The $e/m$ ratio is defined as the charge-to-mass ratio of a particle.For a neutron $(n)$,the charge is $0$,so $e/m = 0$.For an alpha particle $(\alpha)$,the charge is $+2$ and the mass is $4 \ amu$,so $e/m = 2/4 = 0.5$.For a proton $(p)$,the charge is $+1$ and the mass is $1 \ amu$,so $e/m = 1/1 = 1$.For an electron $(e^-)$,the charge is $-1$ and the mass is $1/1837 \ amu$,so $e/m = 1 / (1/1837) = 1837$.Comparing these values: $0 Thus,the increasing order is $n < \alpha < p < e$.

The increasing order for the values of $e/m$ $(\text{charge/mass})$ is :

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