The increasing order of field strength of ligands is:
- A$Cl^{-} < H_2O < NH_3 < CO < CN^{-}$
- B$Cl^{-} < H_2O < NH_3 < CN^{-} < CO$
- C$Cl^{-} < CO < CN^{-} < H_2O < NH_3$
- D$CN^{-} < CO < NH_3 < Cl^{-} < H_2O$
Explore More
Similar Questions
The value of $CFSE$ in a tetrahedral complex having a $3d^4$ configuration of the metal ion,surrounded by strong field ligands,will be:
Medium
View SolutionWhich sets of the $d$-orbitals are directly oriented towards the ligands in octahedral coordination compounds?
Which among the following is a correct order of increasing field strength of ligands?
Identify the complex ion with electronic configuration $t_{2g}^3 e_g^2$.
Match List-$I$ with List-$II$.
List-$I$ (Chromium $(III)$ Complexes) - List-$II$ ($\Delta_o$ $(cm^{-1})$)
$A$. $[Cr(CN)_6]^{3-}$ - $I$. $15,060$
$B$. $[CrF_6]^{3-}$ - $II$. $17,400$
$C$. $[Cr(H_2O)_6]^{3+}$ - $III$. $22,300$
$D$. $[Cr(en)_3]^{3+}$ - $IV$. $26,600$
Choose the correct answer from the options given below:
List-$I$ (Chromium $(III)$ Complexes) - List-$II$ ($\Delta_o$ $(cm^{-1})$)
$A$. $[Cr(CN)_6]^{3-}$ - $I$. $15,060$
$B$. $[CrF_6]^{3-}$ - $II$. $17,400$
$C$. $[Cr(H_2O)_6]^{3+}$ - $III$. $22,300$
$D$. $[Cr(en)_3]^{3+}$ - $IV$. $26,600$
Choose the correct answer from the options given below:
DifficultJEE MAIN 2026
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo