The inductance of a coil is 60,mu H. A curren | vedclass

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(D) The induced $e.m.f.$ $(e)$ in a coil due to self-induction is given by the formula: $e = L \frac{di}{dt}$.Given:Inductance $L = 60\,\mu H = 60 	i

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$3 	imes 10^{-4}\,V$

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(D) The induced $e.m.f.$ $(e)$ in a coil due to self-induction is given by the formula: $e = L \frac{di}{dt}$.Given:Inductance $L = 60\,\mu H = 60 	imes 10^{-6}\,H$.Change in current $di = 1.5\,A - 1.0\,A = 0.5\,A$.Time interval $dt = 0.1\,s$.Substituting these values into the formula:$e = (60 	imes 10^{-6}) 	imes \frac{0.5}{0.1}$$e = (60 	imes 10^{-6}) 	imes 5$$e = 300 	imes 10^{-6}\,V = 3 	imes 10^{-4}\,V$.Therefore,the magnitude of the induced $e.m.f.$ is $3 	imes 10^{-4}\,V$.

The inductance of a coil is $60\,\mu H$. $A$ current in this coil increases from $1.0\,A$ to $1.5\,A$ in $0.1\,s$. The magnitude of the induced $e.m.f.$ is

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