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(C) To find the mean,we use the formula $\bar{x} = \frac{\sum f_{i} x_{i}}{\sum f_{i}}$.First,calculate the product $f_{i} x_{i}$ for each entry:

Vedclass · Accepted Answer

$32.33$

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(C) To find the mean,we use the formula $\bar{x} = \frac{\sum f_{i} x_{i}}{\sum f_{i}}$.First,calculate the product $f_{i} x_{i}$ for each entry:						Marks $(x_{i})$			Students $(f_{i})$			$f_{i} x_{i}$							$15$			$2$			$30$							$22$			$3$			$66$							$28$			$5$			$140$							$31$			$6$			$186$							$35$			$6$			$210$							$40$			$4$			$160$							$44$			$3$			$132$							$46$			$1$			$46$							Total			$30$			$970$			Sum of $f_{i} = 30$.Sum of $f_{i} x_{i} = 30 + 66 + 140 + 186 + 210 + 160 + 132 + 46 = 970$.Mean $\bar{x} = \frac{970}{30} = 32.33$.

The information regarding the marks scored by $30$ students in a $50$ marks test is given below:

Marks $(x_{i})$ $15$ $22$ $28$ $31$ $35$ $40$ $44$ $46$

Number of students $(f_{i})$ $2$ $3$ $5$ $6$ $6$ $4$ $3$ $1$

Find the mean of the data.

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Marks $(x_{i})$	$15$	$22$	$28$	$31$	$35$	$40$	$44$	$46$
Number of students $(f_{i})$	$2$	$3$	$5$	$6$	$6$	$4$	$3$	$1$

The information regarding the marks scored by $30$ students in a $50$ marks test is given below: Marks $(x_{i})$ $15$ $22$ $28$ $31$ $35$ $40$ $44$ $46$ Number of students $(f_{i})$ $2$ $3$ $5$ $6$ $6$ $4$ $3$ $1$ Find the mean of the data.