The instantaneous values of current and volta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The instantaneous current is given by $I = 6 \sin(100 \pi t + \frac{\pi}{4})$.The instantaneous voltage is given by $V = 5 \sin(100 \pi t - \frac{

Vedclass · Accepted Answer

current leads the voltage by $90^{\circ}$

Vedclass · Answer

(D) The instantaneous current is given by $I = 6 \sin(100 \pi t + \frac{\pi}{4})$.The instantaneous voltage is given by $V = 5 \sin(100 \pi t - \frac{\pi}{4})$.The phase of the current is $\phi_I = 100 \pi t + \frac{\pi}{4}$.The phase of the voltage is $\phi_V = 100 \pi t - \frac{\pi}{4}$.The phase difference between current and voltage is $\Delta \phi = \phi_I - \phi_V = (100 \pi t + \frac{\pi}{4}) - (100 \pi t - \frac{\pi}{4}) = \frac{\pi}{4} + \frac{\pi}{4} = \frac{\pi}{2}$.Since $\Delta \phi = \frac{\pi}{2}$ (or $90^{\circ}$) and the phase of the current is greater than the phase of the voltage,the current leads the voltage by $90^{\circ}$.

The instantaneous values of current and voltage in an $AC$ circuit are given by $I = 6 \sin(100 \pi t + \frac{\pi}{4})$ and $V = 5 \sin(100 \pi t - \frac{\pi}{4})$. Then,

Similar Questions

The $r.m.s.$ value of the current $i = 3 + 4 \sin(\omega t + \pi/3)$ is:

An electric bulb rated as $100 \ W-220 \ V$ is connected to an $ac$ source of $rms$ voltage $220 \ V$. The peak value of current through the bulb is: (in $A$)

An $ac$ generator produces an output voltage $E = 170 \sin(377t) \text{ volts}$,where $t$ is in seconds. The frequency of the $ac$ voltage is......$Hz$.

In alternating current circuits,the $a.c.$ meters measure

The alternating current is given by $i = \left\{\sqrt{42} \sin \left(\frac{2 \pi}{T} t\right) + 10\right\} \text{ A}$. The $r.m.s.$ value of this current is $\text{A}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module