The intensity of the magnetic induction field | vedclass

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Question

(A) The formula for the magnetic field at the center of a circular coil is given by $B = \frac{\mu_0 I}{2R}$.Given values are:Permeability of free spa

Vedclass · Accepted Answer

$36 \pi 	imes 10^{-7} ~T$

Vedclass · Answer

(A) The formula for the magnetic field at the center of a circular coil is given by $B = \frac{\mu_0 I}{2R}$.Given values are:Permeability of free space $\mu_0 = 4 \pi 	imes 10^{-7} ~T \cdot m/A$Current $I = 0.9 ~A$Radius $R = 5 ~cm = 5 	imes 10^{-2} ~m$Substituting these values into the formula:$B = \frac{4 \pi 	imes 10^{-7} 	imes 0.9}{2 	imes 5 	imes 10^{-2}}$$B = \frac{3.6 \pi 	imes 10^{-7}}{10 	imes 10^{-2}}$$B = \frac{3.6 \pi 	imes 10^{-7}}{10^{-1}}$$B = 3.6 \pi 	imes 10^{-6} ~T = 36 \pi 	imes 10^{-7} ~T$.

The intensity of the magnetic induction field at the centre of a single turn circular coil of radius $5 ~cm$ carrying a current of $0.9 ~A$ is:

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