The internal energy of one mole of a rigid diatomic gas at absolute temperature $T$ is

  • A
    $3RT$
  • B
    $\frac{5}{2} RT$
  • C
    $\frac{3}{2} RT$
  • D
    $\frac{1}{2} RT$

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If the kinetic energy of a monoatomic gas molecule is $\frac{3}{2}PV$,then the kinetic energy of a diatomic gas molecule is:

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If the internal energy of $n_1$ moles of $He$ at temperature $10T$ is equal to the internal energy of $n_2$ moles of hydrogen $(H_2)$ at temperature $6T$,find the ratio $\frac{n_1}{n_2}$.

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$(A)$ $3$ Translational degrees of freedom $(I)$ Monoatomic gases
$(B)$ $3$ Translational,$2$ rotational degrees of freedom $(III)$ Rigid diatomic gases
$(C)$ $3$ Translational,$2$ rotational and $1$ vibrational degrees of freedom $(IV)$ Non-rigid diatomic gases
$(D)$ $3$ Translational,$3$ rotational and more than one vibrational degrees of freedom $(II)$ Polyatomic gases

Choose the correct answer from the options given below:

State the law of equipartition of energy.

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