The internal resistance of a 2.1, V cell whic | vedclass

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(A) The formula for current $I$ in a circuit with a cell of $EMF$ $\varepsilon$ and internal resistance $r$ connected to an external resistance $R$ is

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$0.5$

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(A) The formula for current $I$ in a circuit with a cell of $EMF$ $\varepsilon$ and internal resistance $r$ connected to an external resistance $R$ is given by:$I = \frac{\varepsilon}{R + r}$Rearranging the formula to solve for internal resistance $r$:$I(R + r) = \varepsilon$$IR + Ir = \varepsilon$$Ir = \varepsilon - IR$$r = \frac{\varepsilon - IR}{I}$Given values:$EMF$ $\varepsilon = 2.1\, V$External resistance $R = 10\,\Omega$Current $I = 0.2\, A$Substituting the values:$r = \frac{2.1 - (0.2 	imes 10)}{0.2}$$r = \frac{2.1 - 2}{0.2}$$r = \frac{0.1}{0.2}$$r = 0.5\,\Omega$

The internal resistance of a $2.1\, V$ cell which gives a current of $0.2\, A$ through a resistance of $10\,\Omega$ is ............. $\Omega$.

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